Question

Can someone please check my work on this math question? please? I'll fan and give a medal!!

Answer 1

Use this equation to answer the question
-4.9t^2 + 24.5t + 117.6 = 0
determine when a ball would be at the height of 49 meters

Answer 2

The height function is h(t) = -4.9t^2 + 24.5t + 117.6

replace h(t) with 49 to get 49 = -4.9t^2 + 24.5t + 117.6

Answer 3

so your goal is to solve 49 = -4.9t^2 + 24.5t + 117.6 for t

get everything to one side and then use the quadratic formula

Answer 4

so would I put 49 in the equation or just leave it out? @jim_thompson5910

Answer 5

Subtract 49 from both sides

Answer 6

oh ok

Answer 7

49 = -4.9t^2 + 24.5t + 117.6
49-49 = -4.9t^2 + 24.5t + 117.6-49
0 = -4.9t^2 + 24.5t + 68.6
Then use the quadratic formula

Answer 8

x = - (-24.5) +/- \/([-24.5]2 - 4*4.9*-68.6)
2(4.9)
x = 24.5 +/- \/1944.81
9.8
T=6.999999999999999, -2

Answer 9

I'm not sure why your calculator isn't saying 7 and instead it says 6.999999999999999

Answer 10

Anyways, you should get t = 7 or t = -2. We ignore t = -2 if t is a time value (which I'm assuming it is) because negative time values make no sense.

So the object reaches 49 meters at t = 7 seconds

Answer 11

thank you so much!!!

Answer 12

you're welcome