Question

What is the solution of log3x + 4 4096 = 4? Can someone help me solve this?

Answer 1

\[\log_{3x+4}4096=4 \]

Answer 2

rewrite it

4^(3x+4) = 4096 hope this will help you

Answer 3

ben how can you rewriting the 4096 like 4 on what power ?

Answer 4

im still not sure how to do it. Could you solve it step by step maybe so I can see how you get the answer?

Answer 5

There's an easier way:
\[4096=4^{6}\]

Answer 6

im trying to figure out what x equals

Answer 7

So in other words:
\[\log_{3x+4}4^{6}=4 \]
\[3x+4=6\]

Answer 8

so you need to know that the function of logarithms is invers of exponential function

Answer 9

should be easy now

Answer 10

yes Parathamesh exactly

Answer 11

3x+4=6 and just this you need to solve it for x

Answer 12

so x=2/3?

Answer 13

yes exactly

Answer 14

that's not one of my answer choices. hold on ill show you

Answer 15

the answers are:
x=-1
x=0
x=4/3
x=3

Answer 16

4*4*4*4*4*4 = 4096

Answer 17

oops sorry i'm wrong

Answer 18

@jhonyy9 shouldn't it be :
\[(3x+4)^{4}=4^{6}\]

Answer 19

so id just solve that?

Answer 20

@benlogic u could probably just substitute the options in that equation to find the answer because expanding that would make it very complicated.

Answer 21

logb(y) = x => y = b^x

Answer 22

log_b y = x so than y = ^x

Answer 23

y = b^x

Answer 24

im still confused, im not sure what to do

Answer 25

so in this case log_b y mean log_(3x+4) 4096

yes ?

Answer 26

3x+4 is b and 4096 mean y

Answer 27

okay, I see that now. what do I do with that

Answer 28

From that u get the equation:
\[(3x+4)^{4}=4^{6}\]

Answer 29

To keep it simple u can just substitute each option in that and check which one is correct.

Answer 30

I think I got it!! x=4/3

Answer 31

so using this formula log_b y = x => y = b^x

Answer 32

Yes that's right

Answer 33

thank, jhonny and pratha, you guys helped a lot. bye

Answer 34

was our pleasure

Answer 35

bye bye