Question

solve

Answer 1

\[3+\sqrt{x+2} = 11\]

the first step would be to get the radical by itself

Answer 2

\[\sqrt{x+2} = 8\]

follow so far?

Answer 3

yea

Answer 4

so now we have to get rid of the square root sign

Answer 5

3?

Answer 6

where did you get 3 from

Answer 7

(x+2)^0.5+3 = 11

(x+2)^0.5 = 11-3

(x+2)^0.5 = 8

Answer 8

it should be 8

\[\sqrt{x+2} = 8\]

\[(\sqrt{x+2})^{2} = 8^{2}\]

Answer 9

so x would be 62

Answer 10

yeah let's check that

Answer 11

\[\sqrt{62+2}+3 = \sqrt{64}+3 => 8+3 = 11 \]

Answer 12

thank you

Answer 13

yeah lol I had my screen minimized so i accidentally put 3 just ignore that