3. Uranium-238 decays into lead. For a given amount of 238U, half is converted to lead every 4.5 million years. a) If a sample is found with 1/8 (0.125) of the expected 238U, how old would this sample be? (2 points) b) For carbon-14, 60,000 years is the maximum age that can be accurately dated. What would be the maximum age of a sample if 238U were used? (3 points)
In 4.5 million years, the amount drops to 1/2 In another 4.5 million years, it'll be 1/2*1/2...
Keep going until it becomes 1/8th
So just divide by 4.5 million years
Not at all. In 4.5 million years, the amount drops to 1/2 In another 4.5 million years, it'll be 1/2*1/2 In another 4.5 million years...
1/2 *1/2*1/2
Yep, now look back at a), and answer it.
Well I need to get to 1/8 right
1/2 *1/2*1/2 = ?
0.125
Right but that isn't the answer. How much TIME did it take? Look back through the posts above.
13.5 million years
For b) you need to look back at one of the other carbon 14 questions you had
"For carbon-14, 60,000 years is the maximum age" how many half lives was that?
6.000
No, how many half lives was there in 60,000 years?
So the age would just be 6,000
You already worked this out once before. If the half life is 6000, then how many half lives is there in 60K years.
10
So it would just be 10years
Nope... think about what the question is asking. If the half life is 6000, then how many ***half lives*** is there in 60K years?
Um wouldn't it be 60000/6000
Yes. But the answer is not 10 YEARS. Read the question carefully.
oh half lives
So 10 half lives
Yes. Now use that For carbon-14, 60,000 years is the maximum age that can be accurately dated. What would be the maximum age of a sample if 238U were used?
Um well we know that 238U, half is converted to lead every 4.5 million years.
"For carbon-14, 60,000 years is the maximum age that can be accurately dated" - how many half lives is that? "What would be the maximum age of a sample if 238U were used?" - same number of half lives, how much time would that be?
divide 238/10 right
No, what is the half life of U238?
119
It tells you in the question. U238 is the name of the element, nothing to do with half life.
"For carbon-14, 60,000 years is the maximum age that can be accurately dated." - we know this is 10 half lives "What would be the maximum age of a sample if 238U were used?" - they are asking how long 10 half lives of U238 is
10*268 then,
238
"U238 is the name of the element, nothing to do with half life."
Half life of U238 is given in the question
lead every 4.5 million years.
So the half life is?
"For carbon-14, 60,000 years is the maximum age that can be accurately dated" - how many half lives is that? "What would be the maximum age of a sample if 238U were used?" - same number of half lives, how much time would that be?
@mathmate
I just don't understand what he means
What the question is telling us is that we can date using carbon-14 for up to 10 half-lives, right?
Yes
ten half-lives of carbon-14 equal 10*6000=60000 year, right?
Right
Since the half-life of C-14 is only 6000 years, we could date a longer period if the half-life had been long, do you agree?
*longer
yes, I do agree
Well, I have to go, so I will finish my reasoning for you to think about. The question seems to say that 10 half-lives is what's limiting the dating process. So if the half-life had been longer, say, a million years, we would have been able to date up to 10 million year. So part b of the question is asking if U238 was used, which has a half-life of 14.5 million years, how far back can we date objects?
Well to see how far back you would divide right
half-life of 6000 years, you can date up to 10 half-lives, so 10*6000 years=60000 years. Now decide on the half-life of U238, and then we can date up to 10 half-lives of U238, and that equals how many years?
1428000
238*6000
@phi
which part are you doing ?
b
Do you know the half-life of C-14 ? (It does not tell me in the question)
6000
60,000 years is the maximum age (using C-14) They are saying that after 60,000 years, the Carbon has disintegrated to almost nothing (too small to measure accurately). How many half-lives is 60,0000 ? in other words, how many times does 6000 go into 60,000 ?
Math mate found the answer up above to How many half-lives is 60,0000 ? in other words, how many times does 6000 go into 60,000 ?
10
So it sounds like the longest we can go is 10 half-lives each radioactive element has a different half-life, but what ever it is, we can only measure back 10 of them.
So the answer is ten?
I think they want the answer in years. The answer is 10 half-lives (for U238) what is that in years ? any idea ?
60,000 years
I guess you don't have the idea. what is the half-life of U238 ? (they tell you in the problem)
It just says For a given amount of 238U, half is converted to lead every 4.5 million years.
ok, and that means half of the 238U disintegrated (into lead) after 4.5 million years that is telling you the "half-life" (how long it takes for ½ of the stuff to disappear)
yes
what is the half-life of U238 ?
4.5?
ugh I'm so confused :/
you are doing good. but not just 4.5 years
4.5 million years
yes. the half-life of 238U is 4.5 million years. now we need to know how many years is 10 half-lives ?
oh so 10*4.5
yes, if you add million years at the end
45million years
yes, you got it.
Thank you so so so much, I really do appreciate it
yw
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