Simplify: (sin Θ − cos Θ) − (sin Θ + cos Θ)2 can someone help?
hello??
-3
click best response
thats not an answer choice
the answer choices are: −sin2 Θ −cos2 Θ 0 −2sin(Θ)cos(Θ) − cos(Θ) + sin(Θ) − 1
well i dont know what to say because i got Simplify the expression. −3
what did you do to arrive to that conclusion?
(sin Θ − cos Θ) − (sin Θ + cos Θ)2 = sin Θ - cos Θ - ( sin^2 Θ + cos^2 Θ + 2 sin Θ cos Θ} Now sin^2 Θ + cos^2 Θ = 1 and 2 sin Θ cos Θ = sin 2Θ - can you continue?
no, i have no idea how to do this
Oh - no need to use that final identity
well replace sin^2 Θ + cos^2 Θ by 1 then just simplify
im still confused, what exactly am i simplifying
sin Θ - cos Θ - ( sin^2 Θ + cos^2 Θ + 2 sin Θ cos Θ} = sin Θ - cos Θ - ( 1 + 2 sin Θ cos Θ}
now distribute the negative over the parentheses and you have the answer
-1-2sin(theta)cos(theta)?
what happened to the first 2 terms?
oh im sorry, let me retry
- the distribution you did is correct
wouldnt they just stay the same in front of what i did?
of course
okay, thats not an answer choice though
can it be further simplified?
no
im not sure whats wrong then the answer choices are: −sin2 Θ −cos2 Θ 0 −2sin(Θ)cos(Θ) − cos(Θ) + sin(Θ) − 1
is it the last one and its just written differently?
Yes they could have changed the fist part to - 2 sine theta but chose not to.
okay, thank you for all your help
* - sin 2 theta
yw
Join our real-time social learning platform and learn together with your friends!