Question

thermo

Answer 1

@imqwerty

Answer 2

I am pretty sure I used the right formula, more concerned about my math.

Answer 3

You took the log only on the left side in step three but not on the right side. Why?

Answer 4

Becuase I wasn't thinking.

Answer 5

fixing

Answer 6

when you apply e to n*ln(v) n will end up looking like e^n * v

Answer 7

you mean \(e^{nln(v)}=e^{n \times v}\) ?

Answer 8

I didn't mean that but that is right. I checked in calculator.

Answer 9

I need to solve for V2

Answer 10

well \(\large e^{ln(v) \times n} \ne e^{v \times n}\)

\(e^{lnv \times n}\) = \((e^{ln(v)})^n\)

\(e^{lnv \times n}\) = \((V)^n\) because \(\color{red}{a^{log_ab}=b}\)

Answer 11

we know \(n,~P_1,~V_1,~P_2\) and now we can simply solve this equation \(P_1V_1^n=P_2V_2^n\) without using log

Answer 12

\(V_1^n=\large \frac{P_2V_2^n}{P_1}\)

\((V_1^n)^{\frac{1}{n}} =\left(\frac{P_2V_2^n}{P_1} \right)^\frac{1}{n}\)

Answer 13

nice, I was over complicating it.

Answer 14

:)

Answer 15

For V2 = 0.0316m^3

Answer 16

yes correct
any ideas about finding the work done

Answer 17

w_b = (P1V1 - P2V2) / 1-n this is what I used.

Answer 18

that is wrong though

Answer 19

yeah that^^ value will come out to be negative
but the work done must be positive because the gas is expanding
this is the correct formula to get the work done-\(\large \frac{P_2V_2-P_1V_1}{n-1}\)

Answer 20

yeah i got a positive answer

Answer 21

I got 21.6kJ

Answer 22

in this case work is done BY the system, other wise work would be done ON the system and the answer would be in kJ

Answer 23

question

Answer 24

yeah i assumed that we are finding the work done by the system and if we want to calculate work done on the system then p1v1-p2v2/(n-1) is correct

Answer 25

I am confused about the difference between refrigerant and ideal gas... my instructor said refrigerant includes ideal gases as well.

Answer 26

How do you distingquish between an ideal gas that falls under refrigerant?

Answer 27

hmm i haven't read about refrigerants can you give me a short description about them

Answer 28

saturations

Answer 29

like water.

Answer 30

xD i don't get it

Answer 31

hmmm maybe i am confusing myself. I will ask her tomorrow after class. Thanks fo ryour help though.

Answer 32

np :)) i'll check refrigerants later