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Mathematics 16 Online
OpenStudy (thatonegirl_):

Find the ratio of the area outside the circle to the area of the square

OpenStudy (thatonegirl_):

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OpenStudy (mathstudent55):

What is the side of the square?

OpenStudy (mathstudent55):

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OpenStudy (thatonegirl_):

2r

OpenStudy (thatonegirl_):

so the area of the inside of the square but outside the circle is \[4r^2-\pi r^2\] ?

OpenStudy (mathstudent55):

\((2r)^2 - \pi r^2 = 4r^2 - \pi r^2\)

OpenStudy (mathstudent55):

Correct.

OpenStudy (mathstudent55):

\(= r^2(4 - \pi)\)

OpenStudy (mathstudent55):

Now find the ratio by dividing by the area of the square.

OpenStudy (thatonegirl_):

\[\frac{ r^2(4-\pi) }{ 4r^2 }\] \[\frac{ 4-\pi }{ 4 }\]

OpenStudy (thatonegirl_):

.215:1 ?

OpenStudy (mathstudent55):

I'd leave it in the exact form as the fraction.

OpenStudy (thatonegirl_):

Okay, thanks!!

OpenStudy (mathstudent55):

Good job! You're welcome.

OpenStudy (mathstudent55):

\(\dfrac{4 - \pi}{4} : 1\)

OpenStudy (thatonegirl_):

Okay thx :)

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