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Find the ratio of the area outside the circle to the area of the square
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|dw:1467050042099:dw|
What is the side of the square?
|dw:1467050075801:dw|
2r
so the area of the inside of the square but outside the circle is \[4r^2-\pi r^2\] ?
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\((2r)^2 - \pi r^2 = 4r^2 - \pi r^2\)
Correct.
\(= r^2(4 - \pi)\)
Now find the ratio by dividing by the area of the square.
\[\frac{ r^2(4-\pi) }{ 4r^2 }\] \[\frac{ 4-\pi }{ 4 }\]
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.215:1 ?
I'd leave it in the exact form as the fraction.
Okay, thanks!!
Good job! You're welcome.
\(\dfrac{4 - \pi}{4} : 1\)
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Okay thx :)
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