Question

3(x+3)^3/4=81
How do I solve this?

Answer 1

\[2\left( x+3 \right)^{\frac{ 3 }{ 4 }}=81=3^4\]

Answer 2

Divide both sides by 3 then raise both equations to the 4/3 power

Answer 3

\[\left\{ 2\left( x+3 \right)^{\frac{ 3 }{ 4 }} \right\}^4=\left\{ \left( 3 \right)^4 \right\}^4\]

Answer 4

or
\[\left( x+3 \right)^{\frac{ 3 }{ 4 }}=\frac{ 81 }{ 2 }\]
\[\left\{ \left( x+3 \right)^{\frac{ 3 }{ 4 }} \right\}^4=\left( \frac{ 81 }{ 2 } \right)^4\]

Answer 5

3(x+3)^3/4=81

(x+3)^3/4=81/3
(x+3)^3/4=27
(x+3)^3* 1/4= 27
[(x+3)^3]^1/4=27
radical order 4 from (x+3)^3=27 |^4

(x+3)^3= (3^3)^4
(x+3)^3=(3^4)^3
x+3=3^4
x+3=81
x=78

Answer 6

i wrote2 which is wrong
actually it is 3

Answer 7

\[\left( x+3 \right)^{\frac{ 3 }{ 4 } \times 4}=27^4=\left( 3^3 \right)^4=3^{3 \times 4}=\left( 3^4 \right)^3\]
\[x+3=3^4=81,x=81-3=78\]