Question

http://prnt.sc/bmbsw8

PLEASE HELP!

Answer 1

The first thing you should do is write the numbers given in order from smallest to largest

Answer 2

What do you get when you sort the data?

Answer 3

2, 4, 5, 6, 6, 7, 8, 9, 10, 10, 10, 11, 11, 26

Answer 4

good

Answer 5

what is the min? how about the max?

Answer 6

2 min, 26 max

Answer 7

yes

Answer 8

what is the median (aka Q2) ?

Answer 9

8?

Answer 10

no

Answer 11

9?

Answer 12

there are 14 values. Since we have an even number of values, the median will be between two data points (in this case between 8 and 9)

add up 8 and 9, then divide by 2

Answer 13

12.5

Answer 14

think of 8 and 9 fighting over the middle. To compromise, we go halfway between 8 and 9 to get to 8.5

(8+9)/2 = 17/2 = 8.5

Answer 15

oh okay!

Answer 16

to get Q1, look at the lower half of the data. Ie, all of the values below the median

find the median of this subset {2, 4, 5, 6, 6, 7, 8}

Answer 17

6

Answer 18

yes

Answer 19

what is the median of this subset

{9, 10, 10, 10, 11, 11, 26}

Answer 20

10

Answer 21

Summary:


min = 2
Q1 = 6
Q2 = median = 8.5
Q3 = 10
max = 26

Answer 22

Thank you!

Answer 23

For 2b, you'll need the interquartile range (IQR)


IQR = Q3 - Q1


Then you'll use this to find the upper fence and lower fence (U and L)


L = Q1 - 1.5*IQR
U = Q3 + 1.5*IQR

Answer 24

If there are any values outside of the fences, then those are the outliers.

Answer 25

okay, this one confuses me XD

Answer 26

tell me what you got for the IQR

Answer 27

what is an IQR?

Answer 28

interquartile range

Answer 29

it's the distance from Q1 to Q3

Answer 30

subtract Q3 and Q1

Answer 31

IQR = Q3 - Q1

Answer 32

ohh then, (Q1) 10 - 6 (Q3)

Answer 33

yes
IQR = Q3 - Q1
IQR = 10 - 6
IQR = 4
agreed?

Answer 34

yes

Answer 35

so 4

Answer 36

use that to find the lower fence

L = Q1 - 1.5*IQR
L = ???

Answer 37

10 - 1.5 times 4 = 4

Answer 38

Q1 isn't 10

Answer 39

ohh 6 - 1.5 times 4 = 0?

Answer 40

yes

Answer 41

Upper fence (U)
U = Q3 + 1.5*IQR
U = ???

Answer 42

10 + 1.5 times 4 = 16

Answer 43

The lower fence is 0. The upper fence is 16. Anything between 0 and 16 is not considered an outlier. Anything outside this boundary is an outlier.


Put another way,
If a value is smaller than the lower fence 0 OR If a value is larger than the upper fence 16
then
the value is an outlier


which values are smaller than 0?
which values are larger than 16?

Answer 44

hmmm, 4?

Answer 45

look through the data set, are there any values smaller than 0?

Answer 46

no

Answer 47

correct

Answer 48

look through the data set, are there any values larger than 16?

Answer 49

yes, 26

Answer 50

so 26 is an outlier

Answer 51

yes

Answer 52

Thank you!

Answer 53

this is what the box plot would look like

Answer 54

no problem