CHECK MY ANSWER!!! EASY CALC. Find the area of the region bounded by the curves y = inverse sine x /2, y = 0, and x = 2 obtained by integrating with respect to y. Your work must include the definite integral and the antiderivative.

Question

erinkb99 · Answer

Points of intersection: sin^-1(x/2)=0
b=2
a=0

sin^-1(x/2) - 0 = sin^-1(x/2)

integral[0, 2] sin^-1(x/2)
1.142

zepdrix · Answer

Woops, they wanted you to integrate in y, not x :o

zepdrix · Answer

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