Question

Randomly drawn from a card deck of 52 cards. Find the probability of drawing a face card

i still dont understand this

Answer 1

@mayankdevnani @habbababba1

Answer 2

@Kayla.M23

Answer 3

how many face cards are there in the pack of 52?

Answer 4

You are actually asking about a conditional probability of an event given the other.

A standard conditional probability answer: Randomly drawing one card, each of the 54 cards in a deck has the same probability of being drawn, i.e.,
1
54
154 . Since there are 13 diamond cards, the probability of drawing a diamond card is
1
54
∗
13
154∗13 ; there are 3 cards that are both face and diamond, so the probability of drawing such a card is 3/54. If you use the conditional probability formula for event B (drawing a card that is diamond and face) given event A (drawing a card that is a diamond),
P
(
B
|
A
)
=
P
(
B
∩
A
)
P
(
A
)
=
3
/
54
13
/
54
=
3
/
13
P(B|A)=P(B∩A)P(A)=3/5413/54=3/13 .
A shortcut way to solve this: since the drawn card is constraint to be a diamond, each of the 13 diamond cards have equal chances of being the drawn card; as only 3 of them are face cards, the probably of actually getting a face card is simply 3/13.

Answer 5

i can count cards so this is a perfect question for me haha

Answer 6

hmmm I can't see how you make this out to be conditional probability

Answer 7

@habbababba1 is that the answer

Answer 8

what are your options

Answer 9

and yes that is the answer

Answer 10

3/13