Question

Given the equation Square root of 2x plus 1 = 3, solve for x and identify if it is an extraneous solution.

Answer 1

x = 4, solution is extraneous
x = 4, solution is not extraneous
x = 5, solution is extraneous
x = 5, solution is not extraneous

Answer 2

@UnkleRhaukus help please!

Answer 3

did you mean: \[\sqrt{2x+1}=3\]
?

Answer 4

yep! i got the answer though, there is another that I need help with that is similar. 2Square root of x minus 5 = 2

Answer 5

\[2\sqrt{x-5}=2\]

Answer 6

what is the domain of x?

Answer 7

im not sure

Answer 8

\[x - 5 \geq0\]

Answer 9

the expression under sqrt has to be greater than or equal to zero

Answer 10

so that's our domain, x >= 5

Answer 11

now divide both equation by 2, and then square them

Answer 12

i got 6.25

Answer 13

\[2\sqrt{x-5} = 2\]
\[\sqrt{x-5} = 1\]
x - 5 =1
x = 6

Answer 14

is it extraneous?

Answer 15

no, because it satisfies the equation. 6 is inside the domain