Question

Will award medal. i don't know how to solve this. What is the vertex form of the equation?
y= -X^2 +12x -4

Answer 1

@Mariamikayla

Answer 2

the maximal point is obtain for a <0 and it's obtained for the equation---> -Delta/4a


a= -1 <0
b=12
c= -4

Delta= b^2-4ac
Delta= 12^2 -4 * (-1)* (-4)= 144 -16= 128

Vertex(f) = - delta/4a = -128/4*(-1) = -128/ -4= 32

Answer 3

i still don't understand why you are using Delta. i never saw that used in the unit before...?

Answer 4

because that's how i've learned :))

Answer 5

f (x) = a(x - h)2 + k

this is vertex form and your answer doesn't look like it is in that form .

Answer 6

i'll try in that form, give me a moment :))

Answer 7

kk

Answer 8

f(x)=a(x-h)^2 + k

h= -b/2a
k= f(h)

a= -1
b= 12
c= 4

h= -12/2*(-1) = -12/-2= 6
h=6

f(x)=ax^2+bx+c <=> f(h)=ah^2+bh+c
k=f(h)=f(6)=a*6^2+b*6+c= 36a+6b+c
k=36a+6b+c=36* (-1)+6*12+4= -36+72+4= -36+76= 40
k=40

f(x)= -a(x-h)^2+k
f(x)= -(-1)(x-6)^2+40
f(x)= (x-6)^2 +40

Answer 9

why are their 3 equations. which one is the answer.?

Answer 10

wait nvm

Answer 11

@Mariamikayla , you have a typo

c = -4

answer is:
-(x-6)^2 +32

Answer 12

ohhh....sorry...