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Mathematics 19 Online
OpenStudy (thephysicsman):

How are the graphs y = kx^2 y = k(x-a)^2 related

OpenStudy (thephysicsman):

I don't want the answer but a hint

jimthompson5910 (jim_thompson5910):

often, graphing will help show you https://www.desmos.com/calculator/m4tjarhbc4

jimthompson5910 (jim_thompson5910):

btw you can replace k and a with any numbers you want in my case, I used k = 1 and a = 2

OpenStudy (thephysicsman):

nice figure, yeah so it seems that the graph is shifted to the right by a units.

jimthompson5910 (jim_thompson5910):

correct

jimthompson5910 (jim_thompson5910):

if 'a' is negative, then the graph shifts to the left |a| units

jimthompson5910 (jim_thompson5910):

you can move the sliders to see it in action

OpenStudy (thephysicsman):

@jim_thompson5910 yeah I'm starting to see this. when a is -ve the graph moved to the left by a units.

OpenStudy (thephysicsman):

is there a specific name for the form k(x-a)^2?

OpenStudy (zzr0ck3r):

for the function \(f(x)\) we have that \(f(x+a)\) movies the graph \(a\) units to the left.

jimthompson5910 (jim_thompson5910):

it's vertex form http://mathbitsnotebook.com/Algebra1/Quadratics/QDVertexForm.html though they used k in a different spot

OpenStudy (thephysicsman):

question is vertex the same as axis of symmetry or no?

OpenStudy (thephysicsman):

\[y = k(x-h)^{2}+k \]

jimthompson5910 (jim_thompson5910):

the vertex is a point (in this case, the point (a,0)) the axis of symmetry is a vertical line (in this case, y = a)

jimthompson5910 (jim_thompson5910):

|dw:1467237274904:dw|

jimthompson5910 (jim_thompson5910):

|dw:1467237284435:dw|

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