Question

what are the center and radius of the circle defined by the equation x2+y2-6x+10y+25=0? I am halfway done with this and I'm stumped by this question

Answer 1

Review this link, and you will be on your way.
http://www.purplemath.com/modules/sqrcircle.htm

Answer 2

can you show me your work?

Answer 3

Honestly, I just search up half of my answers, i rarely ever work out the problems

Answer 4

\[\left( x^2-6x+? \right)+\left( y^2+10y+? \right)=-25+?+? \]

Answer 5

complete the squares
\[\left( \frac{ -6 }{ 2 } \right)^2=9\]
\[\left( \frac{ 10 }{ 2 } \right)^2=25\]

Answer 6

These are the answer choices,

Center 3,-5 Radius 9

Center -3,-5 radius 3

Center 3,-5 radius 3
Center -3,5 radius 9

Answer 7

\[\left( x^2-6x+9 \right)+\left( y^2+10y+25 \right)=-25+9+25\]
\[\left( x-3 \right)^2+\left( y+5 \right)^2=3^2\]
which is of the form
\[\left( x-h \right)^2+\left( y-k \right)^2=r^2\]
center is (h,k) and radius r

Answer 8

can you find the correct option ?

Answer 9

Yes

Answer 10

Thank you so much

Answer 11

yw