Can someone please help me with this math question? Please? I'll fan and give a medal!!
Use the set {(1, 0), (2, 1), (3, 0), (4,2)} for numbers 1 - 3 1. Is the relation a function, why or why not?
@Abbles do you think you could try to help me?
It can only be a function if there is only one y value for each x value. Are you familiar with the vertical line test?
Correction: There can only be one X value for every y value. Meaning, you can't have a point at (2, 4) and a point at (2, 6), since they have the same x value.
I'm somewhat familiar with the vertical line test
Okay. So you know that if you plot the points and draw vertical lines on the graph, two points cannot intersect the same vertical line (they would have the same x value)... if that makes sense.
Do any of your points have the same x coordinate?
so this would be a function because none of them have the same x coordinate?
Correct. There can be two points with the same y-coordinate, but not the same x-coordinate.
Because if two points had the same x-coordinate, they would form a vertical line.
http://www.wolframalpha.com/input/?i=plot+(2,+4)+and+(2,+7) That is point (2, 4) and (2, 7) plotted for you to see. It makes a vertical line.
so the points (2, 4) and (2, 7) are not a function because they have the same x value?
@Abbles
Right.
Your relation, however, is a function. Just as you said.
What is question #2?
this is question 2 2. State the inverse of each relation.
To find the inverse relation, simply swap the x and y values of each coordinate. For example, if the original function had point (5, 7) then the point would become (7, 5) when inversed.
Do that with all of the points in the relation.
{(1, 0), (2, 1), (3, 0), (4,2)} = (0,1) (1,2) (0,3) (2,4) like this?
Perfect!
then what? or is that all?
You could write it f^-1(x) and then state all your values in brackets {like this}
Otherwise, your good! You have the inverse function.
So like this? f^-1(0,1)
And list the rest of the coordinates. There are a few different ways to write functions (you could use f(x) or y or other variables) but you should be good.
So do the rest of the coordinates like that? f^-1(0,1) f^-1(1,2) f^-1(0,3) f^-1(2,4)
@Abbles
No no, it should be all in one function. Like this: f^-1: {(0, 1), (1, 2), (0, 3), (2,4) etc.} But it really depends on how the original function was written. Was it f(x)? Or y = ... ? The above should work. Or just like the coordinates inside of a set of brackets: {(0, 1), (1, 2), (0, 3), (2,4) etc.} ^That way might be best in your situation.
@abbycross167 Still with me?
yes sorry, my WiFi messed up
this is the 3rd question- Is the inverse a function, why or why not?
it won't be a function because (0,1)(0,3) have the same x coordinate. Right? @Abbles
Exactly! You are right. So I would list the inverse function inside brackets {0,1) etc. } instead of using the negative inverse function notation f^-1(x).. since it is not, in fact, a function. :)
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