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Mathematics 23 Online
OpenStudy (abbycross167):

Can someone please help me with this math question? Please? I'll fan and give a medal!!

OpenStudy (abbycross167):

Use the set {(1, 0), (2, 1), (3, 0), (4,2)} for numbers 1 - 3 1. Is the relation a function, why or why not?

OpenStudy (abbycross167):

@Abbles do you think you could try to help me?

OpenStudy (abbles):

It can only be a function if there is only one y value for each x value. Are you familiar with the vertical line test?

OpenStudy (abbles):

Correction: There can only be one X value for every y value. Meaning, you can't have a point at (2, 4) and a point at (2, 6), since they have the same x value.

OpenStudy (abbycross167):

I'm somewhat familiar with the vertical line test

OpenStudy (abbles):

Okay. So you know that if you plot the points and draw vertical lines on the graph, two points cannot intersect the same vertical line (they would have the same x value)... if that makes sense.

OpenStudy (abbles):

Do any of your points have the same x coordinate?

OpenStudy (abbycross167):

so this would be a function because none of them have the same x coordinate?

OpenStudy (abbles):

Correct. There can be two points with the same y-coordinate, but not the same x-coordinate.

OpenStudy (abbles):

Because if two points had the same x-coordinate, they would form a vertical line.

OpenStudy (abbles):

http://www.wolframalpha.com/input/?i=plot+(2,+4)+and+(2,+7) That is point (2, 4) and (2, 7) plotted for you to see. It makes a vertical line.

OpenStudy (abbycross167):

so the points (2, 4) and (2, 7) are not a function because they have the same x value?

OpenStudy (abbycross167):

@Abbles

OpenStudy (abbles):

Right.

OpenStudy (abbles):

Your relation, however, is a function. Just as you said.

OpenStudy (abbles):

What is question #2?

OpenStudy (abbycross167):

this is question 2 2. State the inverse of each relation.

OpenStudy (abbles):

To find the inverse relation, simply swap the x and y values of each coordinate. For example, if the original function had point (5, 7) then the point would become (7, 5) when inversed.

OpenStudy (abbles):

Do that with all of the points in the relation.

OpenStudy (abbycross167):

{(1, 0), (2, 1), (3, 0), (4,2)} = (0,1) (1,2) (0,3) (2,4) like this?

OpenStudy (abbles):

Perfect!

OpenStudy (abbycross167):

then what? or is that all?

OpenStudy (abbles):

You could write it f^-1(x) and then state all your values in brackets {like this}

OpenStudy (abbles):

Otherwise, your good! You have the inverse function.

OpenStudy (abbycross167):

So like this? f^-1(0,1)

OpenStudy (abbles):

And list the rest of the coordinates. There are a few different ways to write functions (you could use f(x) or y or other variables) but you should be good.

OpenStudy (abbycross167):

So do the rest of the coordinates like that? f^-1(0,1) f^-1(1,2) f^-1(0,3) f^-1(2,4)

OpenStudy (abbycross167):

@Abbles

OpenStudy (abbles):

No no, it should be all in one function. Like this: f^-1: {(0, 1), (1, 2), (0, 3), (2,4) etc.} But it really depends on how the original function was written. Was it f(x)? Or y = ... ? The above should work. Or just like the coordinates inside of a set of brackets: {(0, 1), (1, 2), (0, 3), (2,4) etc.} ^That way might be best in your situation.

OpenStudy (abbles):

@abbycross167 Still with me?

OpenStudy (abbycross167):

yes sorry, my WiFi messed up

OpenStudy (abbycross167):

this is the 3rd question- Is the inverse a function, why or why not?

OpenStudy (abbycross167):

it won't be a function because (0,1)(0,3) have the same x coordinate. Right? @Abbles

OpenStudy (abbles):

Exactly! You are right. So I would list the inverse function inside brackets {0,1) etc. } instead of using the negative inverse function notation f^-1(x).. since it is not, in fact, a function. :)

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