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Mathematics 16 Online
OpenStudy (noodya123):

What is the solution to the inequality below ? x^2 >= 49 A. X <=-7, or X >= 7 B. x >= 7 C. -7 <= x <= 7 D. x <-7, or x>7

OpenStudy (rockysistrunk):

b

OpenStudy (noodya123):

thank you how if you dont mind explaining

OpenStudy (rockysistrunk):

square root 49 and you get 7. you square root because you have x^2, so you square root 49 and you get 7

OpenStudy (noodya123):

thank you

OpenStudy (rockysistrunk):

no problem

zepdrix (zepdrix):

Hey Noodya :) When you take the square root of a square, you end up with a fancy plus/minus symbol in front of the result.\[\large\rm \sqrt{x^2}=\pm x\]So in our problem here, when we take the square root of each side, we get,\[\large\rm \pm x\ge7\]We will have two solutions for x from this point.

zepdrix (zepdrix):

When x is positive we have \(\large\rm +x\ge7\) When x is negative we have \(\large\rm -x\ge7\) In the negative case, you'll need to multiply the negative to the other side. Remember what happens when you multiply a negative across an inequality?

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