Mathematics
8 Online
OpenStudy (phebe):
A transformer consists of 250 primary windings and 725 secondary windings. If the emf of the primary coil is 20.0 V, what is the emf across the secondary coil?
A- 29.0 V
B- 18.1 V
C- 58.0 V
D- 34.5 V
9 years ago
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OpenStudy (phebe):
i think its gonna be 58.0
9 years ago
OpenStudy (phebe):
i think you multiply the emf not sure
9 years ago
OpenStudy (phebe):
theres a formula for this right?
9 years ago
OpenStudy (mayankdevnani):
yeah !
\[\large \bf \frac{secondary~windings}{primary~widnings}=\frac{EMF~secondary}{EMF~primary}\]
9 years ago
OpenStudy (mayankdevnani):
just plug all the values and get your answer
9 years ago
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OpenStudy (phebe):
okay thanks!
9 years ago
OpenStudy (phebe):
let me see what i get
9 years ago
OpenStudy (mayankdevnani):
sure!
9 years ago
OpenStudy (phebe):
725/250 right?
9 years ago
OpenStudy (mayankdevnani):
yep! this is your left hand side fraction
9 years ago
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OpenStudy (phebe):
okay so its 2.9
9 years ago
OpenStudy (phebe):
So is it A?
9 years ago
OpenStudy (mayankdevnani):
right !
9 years ago
OpenStudy (phebe):
YES! THANK YOUUU!!!! <3
9 years ago
OpenStudy (mayankdevnani):
\[\large \bf \frac{725}{250}=\frac{x}{20}\]
9 years ago
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OpenStudy (mayankdevnani):
find x ?
9 years ago
OpenStudy (phebe):
SO DIVIDE 250 and 20?
9 years ago
OpenStudy (mayankdevnani):
\[\large \bf 2.9=\frac{x}{20}\]
9 years ago
OpenStudy (mayankdevnani):
multiply both sides by 20,we get
\[\large \bf 2.9 \times 20=x\]
9 years ago
OpenStudy (mayankdevnani):
now solve for x
9 years ago
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OpenStudy (phebe):
so its 58
That means my original answer was always right
thanks!
9 years ago
OpenStudy (mayankdevnani):
np !
9 years ago