Find the sum of the infinite series 1 + 2 + 4 + 8 +…if it exists. 32,767 65,535 131,071 none
numbers get bigger and bigger right?
therefore so does the sum
inb4 \(-\dfrac1{12}\)
??
http://www.urbandictionary.com/define.php?term=inb4&defid=3632151 Since \(-\dfrac1{12}\) is Ramanujan sum, and this "math astounding fact" is so common, it's annoying. Just little tease, sorry
\[S=1+2+4+8+\cdots\]\[2\times S=2+4+8+16+\cdots\]\[1+2S=1+2+4+8+\cdots\]\[1+2S=S\]\[1+S=0\]\[S=-1\]
@Kainui the proof falls apart when you go from `1+2S = S` to `1+S = 0`. Subtracting S from both sides has you using the form `infinity - infinity` but that's indeterminate.
@jim_thompson5910 I think he was just continuing the discussion of Ramanujan sum, which in that case, it's technically valid. It's just a way to assign value to divergent series.
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