Wan has 22 bulbs of the same shape and size in a box. The colors of and amounts of the bulbs are shown below:

6 blue bulbs
9 red bulbs
7 orange bulbs

Without looking in the box, Wan takes out a bulb at random. He then replaces the bulb and takes out another bulb from the box. What is the probability that Wan takes out an orange bulb in both draws?

7 / 22 * 7 / 22 = 49 / 484

7 / 22 * 6 / 21 = 42 / 462

7 /22 + 6 / 21 = 279 / 462

7 / 22 + 7 / 22 = 308 / 484

Question

Wan has 22 bulbs of the same shape and size in a box. The colors of and amounts of the bulbs are shown below:

    6 blue bulbs
    9 red bulbs
    7 orange bulbs

Without looking in the box, Wan takes out a bulb at random. He then replaces the bulb and takes out another bulb from the box. What is the probability that Wan takes out an orange bulb in both draws?

7 / 22  *  7 / 22 = 49 / 484

7 / 22 * 6 / 21 = 42 / 462

7 /22 + 6 / 21 = 279 / 462

7 / 22 + 7 / 22 = 308 / 484

nikki_skellington · Answer

i think this one is C (7 /22 + 6 / 21 = 279 / 462) am i right?

jim_thompson5910 · Answer

A = probability of orange = (# of orange)/(# total) = 7/22

probability of 2 oranges = (A)*(A) = (7/22)*(7/22)

this only works if you put the bulb back

nikki_skellington · Answer

ok thank you, again lol

jim_thompson5910 · Answer

np