Question

In the reaction MgCl2 + 2KOH→ Mg(OH)2 + 2KCl, if 6 mole MgCl2 are added to 6 moles KOH, which is the limiting reagent?

Answer 1

Ok, to basically what this means is which compound will run out of itself before the other. (Example would be, you have 2 runners sprinting, which one gets tired and stops before the other one)

That's essentially what its asking.

Do you know how to do conversation
@davante_fresh

Answer 2

No

Answer 3

The limiting reagent is the one that doesn't allow you to obtain more product. It sounds obvious but let me explain:
What you need to know first is that every chemical reaction is different, If you are trying to obtain ammonia from N2 and H2 you will (theoretically) use a pre fixed amount of both reagents to yield certain amount of products.
1 mole of N2 react with 3 mole of H2 to yield 2 mole of NH3. However this is all theoretical, you have no way of telling if it's all gonna react until you go ahead and put this in a reactor, and afterwards you measure your yield. In reality If you put x amount of said reagents you will most likely not get what you calculated you would. That's why we calculate the yield of each reaction to determine what's the limiting reagent and what's the one in excess.
In your case check the stoichiometry, do equal amount of reagents react completely to yield 100% of product?
Remember that 1 mole of magnesium chloride react with 2 mole of potassium hydroxide.
You have 6 moles of magnesium chloride, and 6 moles of potassium hydroxide how many moles of both do you need for your reagents to react ( 'dissappear' ) completely to yield x mole of product.
Which one is in excess?

Answer 4

@tatianagomez yeah i agree with u .
@davante_fresh Limiting agent is the reactant that limits the reaction.
Here we have 2 reactants which are MgCl2 and KOH and they react according to 1:2 stoichiometry . That means it needs 1 mole of MgCl2 to react with 2 moles of KOH
We are said we are given with 6 moles of each of the reactants right? So if we have 6 moles of KOH, it will only require 3 moles of MgCl2 right ? (look at the stoichiometric ratio )
But we have 6 moles of MgCl2 anyway which means we have 3 more moles (6-3) remaining from MgCl2 after reacting with all the moles of KOH. There's MgCl2 in excess but KOH is over. That is KOH limits the reaction. Therefore KOH is the limiting agent