A sequence of transformations maps ∆ABC to ∆A′B′C′. The sequence of transformations that maps ∆ABC to ∆A′B′C′ is a reflection across the(a.y-axis, b.x-axis, c.line y=x, d.line y=-x) followed by a translation (a.4 units to the right and 10 units up, b. 8 units to the right and 4 units up, c. 10 units to the right and 2 units up, d. 10 units to the right and 4 units up) pls help ive been stuck on this question for days
I cant do this one. Are you sure you have the question right?
Oh hold on . I think the first part is a refection in the line y = x
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Yes thats correct Now what do you think the translation is?
we need to figure out what the coordinates of C' we cant guess them form the diagram i've drawn which is only a rough one.
the line does not pass throughthe origin as ive drawn it.
well when i got help from my teacher he'd said 4 units to the right and 10 units up but i think he may have given me the incorrect answer bcos i got it wrong :/
the point C has coordinates (-4,2) and a reflection of this in the line y=x will be at (2,-4) beacause a line perpendicular to it as equation y = -x
so for this point to get tom C' in your duagram the translation will be 10 units to the right and how many units up?
* get to
4 units up?
right
AHHH thanks so the answer is line y=x and 10 units to the right and 4 units up?
because we are going from 2 to 12 in x direstion and from -4 to 0 in the y driection
yes
thanks so much!!!!! you really helped
good yw
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