Question

who knows about Arithmetic series????????????
will medal & fan

Answer 1

A lot of people

Answer 2

r u

Answer 3

Just ask the question already lol

Answer 4

lol k

Answer 5

Mike started a savings account by depositing $9. Each month, he deposits more money than the month before. At the end of 41 months, he has saved $9,389.00. How much more does he deposit each month?

$11.00
$11.50
$12.00
$12.50

Answer 6

?

Answer 7

hopefully you have seen this\[\large a_n = a_1 + (n-1)d\]a1 is first term, d is common difference

and \[\large S_n = \frac{ n(a_1+a_n) }{ 2 }\]where Sn is the sum of the first n terms

Answer 8

OH SO HOW WOULD WE DO THT

Answer 9

started a savings account by depositing $9 - so a1 = 9
end of 41 months - so n =41
he has saved $9,389.00 - so Sn = 9,389
How much more does he deposit each month? - we need to find d

First, plug all those numbers into the second formula, the Sn one

Answer 10

ok

Answer 11

so how would that even look like

Answer 12

\[\large S_n = \frac{ n(a_1+a_n) }{ 2 }\]
plug in
a1 = 9
n =41
Sn = 9,389