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Mathematics 9 Online
OpenStudy (abbles):

Check my answer? Exponents

OpenStudy (abbles):

Check all correct answers (there may be more than one). In the expression a^b, A. The value b is an exponent. B. The value a tells you how many times to multiply b by itself. C. The value a must be > 1. D. The value b tells you how many times to multiply a by itself. E. The value b must be an integer.

OpenStudy (afloridagirl):

a,d,e i believe

OpenStudy (afloridagirl):

i can explain if you want

OpenStudy (calculusxy):

With exponents you would have a base and the exponent itself. For example, in: \[\huge x^\color{red}{y}\] \(x\) is the `base` \(y\) is the `exponent`

OpenStudy (abbles):

I got A and D... why would E be correct?

OpenStudy (afloridagirl):

tbh i am probably wrng when it comes to saying its e

OpenStudy (abbles):

Hahh :P Well thanks for trying

OpenStudy (afloridagirl):

i have more of a gut feeling with that one, im sorry

OpenStudy (calculusxy):

E does not necessarily have to be an integer. It can be a fraction as well. For example: \(2^{\frac{1}{2}}\)

OpenStudy (abbles):

That's what I thought... so the only two that are correct are A and D?

OpenStudy (whpalmer4):

exponents may be numbers other than integers. for example\[x^{1/2}=\sqrt{x}\]

OpenStudy (whpalmer4):

yes only A&D

OpenStudy (calculusxy):

Yes that is because you can take the format: \[\huge x^{\frac{a}{b}} = \sqrt[b]{x^a}\]

OpenStudy (abbles):

Okay, thanks everyone :)

OpenStudy (calculusxy):

You're welcome :)

OpenStudy (calculusxy):

@Abbles I just put the square root thing out there although it won't be of much importance to you if you're not a Algebra 2/Trig student.

OpenStudy (abbles):

Actually I'm in Precalc :P

OpenStudy (calculusxy):

Ok lol. Never mind so you get it :)

OpenStudy (abbles):

Haha yeah :) Do you mind checking one more exponent related question? Simplify the expression below. Write your answer with only positive exponents. \[(a^2b^2c)/(a^5c^3) * (a^3b/c^4)\]

OpenStudy (abbles):

I got b^3/b^5

OpenStudy (calculusxy):

Let me check :) \[\frac{a^2b^2c}{a^5c^3} \times \frac{a^3b}{c^4} = a^{-3}b^2c^{-2} \times \frac{a^3b}{c^4} = \frac{b^2}{a^3c^2} \times \frac{a^3b}{c^4} = \frac{a^3b^3}{a^3c^6} = \frac{b^3}{c^6}\]

OpenStudy (abbles):

Woops, I meant b^3/c^5. And I also did a typo on the question, it should be a^5c^2 on the denominator of the first term... but thanks for showing your work! Looks all good. :)

OpenStudy (calculusxy):

That's great!

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