Question

please help!

Answer 1

The distance traveled, in meters, of a coin dropped from a tall building is modeled by the equation d(t) = 4.9t2 where d equals the distance traveled at time t seconds and t equals the time in seconds. What does the average rate of change of d(t) from t = 3 to t = 6 represent?

The coin travels an average distance of 44.1 meters from 3 seconds to 6 seconds.
The coin falls down with an average speed of 14.7 meters per second from 3 seconds to 6 seconds.
The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.
The coin travels an average distance of 14.7 meters from 3 seconds to 6 seconds.

Answer 2

i believe it is c or a

Answer 3

i mean a or b

Answer 4

@afloridagirl I'll answer yours if you answer mine

Answer 5

Plug in t = 3 to get
d(t) = 4.9t^2
d(3) = 4.9*(3)^2
d(3) = ________ (fill in the blank)

Answer 6

44.1?

Answer 7

yes, now plug in t = 6
d(t) = 4.9t^2
d(6) = 4.9*(6)^2
d(6) = ________ (fill in the blank)

Answer 8

176.4?

Answer 9

yes

Answer 10

oh good

Answer 11

change in distance = 176.4 - 44.1 = 132.3
change in time = 6 - 3 = 3

The object travels 132.3 meters in 3 seconds

the speed is the ratio of the two values

speed = distance/time
speed = 132.3/3
speed = 44.1 meters per second

This is the average speed of the object from t = 3 to t = 6 seconds. This is equivalent to the slope of the straight line through the two points.

Answer 12

so its a?

Answer 13

`meters per second` is the same as meters/second (meters over seconds)

Answer 14

look closely at the units

Answer 15

and look for keywords such as "distance" and "speed"

Answer 16

so c?

Answer 17

???

Answer 18

yes ` The coin falls down with an average speed of 44.1 meters per second from 3 seconds to 6 seconds.`

Answer 19

thank you so much!

Answer 20

can you help with another one?

Answer 21

@jim_thompson5910

Answer 22

sure, post a new thread