Question

Can someone please help me with this math question? Please? I'll fan and give a medal!!

Answer 1

Find the inverse of x^2/2. Is the inverse a function? Explain

Answer 2

\[\Large f(x) = \frac{x^2}{2}\]
\[\Large y = \frac{x^2}{2}\]
\[\Large x = \frac{y^2}{2}\]
now solve for y

Answer 3

Y=\/2x
@jim_thompson5910

Answer 4

you mean
\[\Large y = \sqrt{2x}\]
right?

Answer 5

Yes sir

Answer 6

you forgot about the fact that if x^2 = 25 then x = 5 or x = -5

Answer 7

so there should be a plus/minus
\[\Large y = \pm \sqrt{2x}\]

Answer 8

So I could write it like this?
Y=\/2x
or
Y=-\/2x

Answer 9

yes

Answer 10

you can write sqrt(x) to signify \(\Large \sqrt{x}\)

Answer 11

graph both of the equations together. Is it possible to pass a vertical line through more than one point on the graph?

Answer 12

think of the two curves as one big curve

Answer 13

yes a vertical line can

Answer 14

so it fails the vertical line test, meaning that the inverse is NOT a function

Answer 15

Okay thank you very much for helping me!!

Answer 16

np