Question

Help!

Question below

Answer 1

Solve for x for 0 <_ x < 2pi

cotxcosx-cotx=0

Answer 2

The multiple answer choices are

0

Pi/2

Pi

3pi/2

2/pi

Answer 3

\[\cot x \left( \cos x-1 \right)=0,\cot x=0=\cot \frac{ \pi }{ 2 },\cot \frac{ 3\pi }{ 2 },x=\frac{ \pi }{ 2 },\frac{ 3\pi }{ 2 }\]
\[\cos x=1=\cos 0,x=0\]
when x=0,cot x is undefined.

Answer 4

cotxcosx-cotx=0

cosx cosx
----- *cosx - ----- = 0
sinx sinx