Set up a definite integral that represents the volume obtained by rotating the region between the curve y^2=x and y^2=2(x-1) about the lines below.
(a) Rotate about the y-axis
(b) Rotate about the line y=3
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OpenStudy (dido625):
Normally, I am okay with elementary calculus but I always struggle with this part. Any guidance?
OpenStudy (nincompoop):
first, try and draw
OpenStudy (dido625):
I already drew out the region. Looks like a washer to me.
OpenStudy (nincompoop):
how do you determine between washer and shell method?
OpenStudy (dido625):
Inner and outer radius for Washer and cylinders.
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OpenStudy (nincompoop):
or even disk
OpenStudy (dido625):
Yea. Disk too.
OpenStudy (nincompoop):
so if you already know that it is washer, then you just have to use the formula
OpenStudy (dido625):
I know. I'm just having writing it out xD xD .Hold on.
OpenStudy (dido625):
\[\int\limits_{a}^{b}\pi(x^2-(2(x-1))^2 dx\]
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OpenStudy (dido625):
Is that it? I can easily find a and by setting the two equations equal to each other.