I need help with this question 1) Find the area of a regular hexagon with the given measurement. 48-inch perimeter A = sq. in. A =
You need to write one question per post. I'll help you with the first one here.
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The perimeter is 48 inches. What is the length of each side?
Uh, 8?
Yes. Now we can divided the hexagon into 6 congruent triangles. |dw:1467666193119:dw|
The area of the hexagon is 6 times the area of each triangle. What do you need to know to be able to find the are of a triangle?
The length of each side?
There is a way to find the area that way, but the more common way is to know the base and the height.
Let's look at the hexagon. The point inside where all the triangles meet is the vertex of 6 congruent angles. Altogether, the 6 angles go around a full circle, so altogether they measure 360 degrees. Each angle measures 360 deg/6 = 60 deg. |dw:1467666388394:dw|
Also, a polygon of n sides has the sum of the measures of the interior angles 180(n - 2) For our hexagon, with 6 sides, n = 6, so 180(6 - 2) = 180(4) = 720 The sum of the measures of the interior angles is 720 deg. That means each interior angle is 120 deg.
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