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Mathematics 16 Online
OpenStudy (mathidiot):

I need help with this question 1) Find the area of a regular hexagon with the given measurement. 48-inch perimeter A = sq. in. A =

OpenStudy (mathstudent55):

You need to write one question per post. I'll help you with the first one here.

OpenStudy (mathstudent55):

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OpenStudy (mathstudent55):

The perimeter is 48 inches. What is the length of each side?

OpenStudy (mathidiot):

Uh, 8?

OpenStudy (mathstudent55):

Yes. Now we can divided the hexagon into 6 congruent triangles. |dw:1467666193119:dw|

OpenStudy (mathstudent55):

The area of the hexagon is 6 times the area of each triangle. What do you need to know to be able to find the are of a triangle?

OpenStudy (mathidiot):

The length of each side?

OpenStudy (mathstudent55):

There is a way to find the area that way, but the more common way is to know the base and the height.

OpenStudy (mathstudent55):

Let's look at the hexagon. The point inside where all the triangles meet is the vertex of 6 congruent angles. Altogether, the 6 angles go around a full circle, so altogether they measure 360 degrees. Each angle measures 360 deg/6 = 60 deg. |dw:1467666388394:dw|

OpenStudy (mathstudent55):

Also, a polygon of n sides has the sum of the measures of the interior angles 180(n - 2) For our hexagon, with 6 sides, n = 6, so 180(6 - 2) = 180(4) = 720 The sum of the measures of the interior angles is 720 deg. That means each interior angle is 120 deg.

OpenStudy (mathstudent55):

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