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Mathematics 8 Online
OpenStudy (amtran_bus):

Can't use a calculator

OpenStudy (amtran_bus):

\[\frac{2 ^{30} -2^{29}}{ 2 }\]

OpenStudy (amtran_bus):

Can I reduce it? Like 2^4-2^3 / 2 and it turn out the same?

OpenStudy (mathstudent55):

Factor out 2^29 from the numerator.

OpenStudy (amtran_bus):

Hum. Can you show me how to do that with the exp? I understand factoring but I'm afraid I will kill it.

OpenStudy (mathstudent55):

Example: \(x^{30} - x^{29} = x^{29}(x - 1)\) Now replace x with 2.

OpenStudy (mathhelp97):

if you have android download the app called wabbitemu it will give you a texas instraments calcator

ganeshie8 (ganeshie8):

Suppose you have `n` apples. If you throw away half of them, how many apples you will be left with ?

OpenStudy (amtran_bus):

*Without a calculator* Ok @mathstudent55 \[\frac{ 2^{29}(x-1) }{ 2 }\]

OpenStudy (mathstudent55):

Replace x with 2 in the parentheses also.

OpenStudy (amtran_bus):

Oh yea my bad

OpenStudy (amtran_bus):

\[\frac{ 2^{29}(2-1) }{ 2 }\]

OpenStudy (mathstudent55):

Now what is 2 - 1? It's just numbers, so you can do the subtraction.

OpenStudy (amtran_bus):

1

OpenStudy (amtran_bus):

So just 2^29 on top

OpenStudy (mathstudent55):

Right, so you have \(\dfrac{2^{29}}{2^1} \) How do you divide powers with the same base?

OpenStudy (amtran_bus):

Subtract, right?

OpenStudy (mathstudent55):

Correct.

OpenStudy (amtran_bus):

So I am at \[2^{28}\]

OpenStudy (mathstudent55):

That is correct.

OpenStudy (amtran_bus):

Ok. Well, thankfully I can stop there...it does not want an actual number value. Thanks!

OpenStudy (mathstudent55):

Now just give me a minute. Look above at what @ganeshie8 wrote.

OpenStudy (mathstudent55):

Notice that when you have powers of 2, each next higher integer power is 2 times the previous power. This is what I mean. For example, \(2^{30} = 2^{29} \times 2\) \(2^{15} = 2^{14} \times 2\) In general, \(2^{n + 1} = 2^n \times 2\) Ok so far?

OpenStudy (amtran_bus):

Yes, I follow.

OpenStudy (amtran_bus):

And thanks for taking so much time to explain this BTW.

OpenStudy (mathstudent55):

That means each power of 2 is half of the next higher integer power of 2. In general \(2^n = \dfrac{2^{n + 1}}{2} \) That means, for the powers used in this problem, \(2^{29} = \dfrac{2^{30}}{2} \)

OpenStudy (amtran_bus):

Wow thanks so much!

OpenStudy (mathstudent55):

That means in the numerator of the fraction, where you have \(2^{30} - 2^{29}\), you are subtracting half of \(2^{30}\). Then you can conclude immediately that \(2^{30} - 2^{29} = 2^{29} \)

OpenStudy (mathstudent55):

Then when you divide \(2^{29}\) by 2, as the denominator of the fraction shows, you get \(2^{28} \)

OpenStudy (mathstudent55):

This second approach is all based on what @ganeshie8 asked above.

OpenStudy (mathstudent55):

You're welcome.

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