how much money invested at 5% compounded contentiously for 3 years will result in $820?
continuously**
Any ideas on where to start?
Use F = (1+P)^n where P is the present cost, F is the final cost, and n is the # of years.
okay then what?
Plug in the info into the formula
??
\(\color{#0cbb34}{\text{Originally Posted by}}\) @raffle_snaffle Use F = (1+P)^n where P is the present cost, F is the final cost, and n is the # of years. \(\color{#0cbb34}{\text{End of Quote}}\) Thise
yeah i saw that. but where did it come from?
That is the formula we would use to find out how much money is being invested
oh. i didn't know that.
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would that be it?
\[\huge~\rm~\bf~A=P(1+\frac{ r }{ 100 })^n\] We know: A=820 n=3 r=5 Now you just have to find P So plug in the given info into that equation
what. you told me to use that first equation. i am confused. what is this second equation have to do with anything.
We use the compound interest formula to find investment the other user made a mistake as did I, I apologize.
okay.... so what is this second equation?
i don't know how to use that one.
Compound interest formula plug in the info I gave you and you basically solve for P .
i don't know how to solve that complex of an equation.
my calculator broke otherwise i would just use that to solve it.
\(\color{#0cbb34}{\text{Originally Posted by}}\) @pooja195 \[\huge~\rm~\bf~A=P(1+\frac{ r }{ 100 })^n\] We know: A=820 n=3 r=5 Now you just have to find P So plug in the given info into that equation \(\color{#0cbb34}{\text{End of Quote}}\) \[\huge~\rm~\bf~820=P(1+\frac{ 5 }{ 100 })^3\] Solve for p.. give it a try
i can't do that without a calculator. it is way to complicated to do without one.
i don't know how to solve this complex on paper.
why are there so many people on my post that aren't even doing anything. if you can't help on this question plz go help on my other one.
If you aren't gonna try and just troll there isn't really a point in helping you.
You are dealing with continuous compounding. You need the formula that deals with that. It uses the constant e.
im seriously not. my calculator broke. and i didn't learn how to solve these types of things on paper. iv always just used a calculator. i am not trying to troll i sware.
dragon 1) you need a CONTINUOUS compounding formula and 2) I am looking for the formula to post here.
\(\Large A = Pe^{rt} \)
what. more formulas. now i am more confused oh my.
how do i solve that formula now then if i need that one?
You would get the same answer with either formula.
You have the end amount, A. You are looking for P. e is a famous math constant. r = 5% = 0.05 t = 3
Here it is:
Continuous compounding yields more interest than periodic compounding.
okay. so then what?
iv never even seen this formula before.
\(\Large A = Pe^{rt} \) \(\Large 820 = Pe^{0.05 \times 3} \) \(\Large P = \dfrac{820}{e^{0.15}} \)
5% 3 years $820 Principal = Total / e^[rate * years] Principal = 820 / e^.15 (which is what mathstudent just posted)
okay. so that is the answer?
Use a calculator. A scientific calculator can raise e to an exponent.
my calculator broke. well the batteries died i don't have money for more.
I think you've trolled enough. Good bye.
scientific calculator is so expensive i have never owned one
Use google. It will solve it for you. :3
i am not trolling. these people are helping me lots. it is starting to make sence. you havent helpes at all pooja
thanks guys. i didn't know there was one online. give me a sec then.
No you have to do the computing. but your calculator is broken? dragon here is an online calculator : http://www.1728.org/calc.htm it WILL raise numbers to a power
705.780540669 this was the answer it showed. this correct?
That's not the answer I got.
Correct.
it is what the calculator online showed.
although i don't think you can invest money with so many numbers after that decimal point.
Sorry, I recalculated. That answer is correct.
If you do annual compounding, then the answer is $708.35 It makes sense that if you do annual compounding you have to start with a little more principal because continuous compounding yields more interest that periodic compounding.
oh okay thanks. can you guys help with my question in mathematics please?
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