Question

Factor completely.
-2k - k3 - 3k2

k(-k + 1)(k - 2)
-k(k - 1)(k - 2)
-k(k + 1)(k + 2)

Answer 1

@hartnn

Answer 2

first factor out the 'k' from all the terms,
what do you get?

Answer 3

I'm not sure. I'm not very good with this kind of math.

Answer 4

\(\large ☻☺+☻♥= ☻(☺+♥) \\ \text{this is factoring, } \\ \text{☻ was common from both terms and factored out.}\)

So in,
\(-k^3 -3k^2 -2k\)
there is one 'k' which is common in all the terms!

factor that out.

Answer 5

-k(k^2 + 3k - 2)?

Answer 6

very good try!
from -2k, if we factor -k, we get +2,

so it is
\(\Large -k(k^2 +3k+2)\)

Answer 7

now,
can you tell me 2 numbers whose sum is +3 and product is +2 ?

Answer 8

what are you confused about?

Answer 9

I'm not good with polynomials. I haven't been good since I've started studying them.

Answer 10

It takes a lot of practice...

Answer 11

...have you tried the khan academy?

Answer 12

go back to the very beginning definition of a polynomial and work your way through the videos

Answer 13

by that time, go through this steps and let me know if any doubt:
\(k^2 +3k +2 = k^2 + 2k+k+2 = k(k+2) + 1(k+2) = (k+1)(k+2)\)

so yes,
-k(k+1)(k+2) is indeed correct.