Question

Find a cubic function with the given zeros.

Square root of six., - Square root of six., -3

Answer 1

@Mehek14 @ganeshie8 @mayankdevnani

Answer 2

If \(\sqrt{6}\), \(\sqrt{6}\), \(3\) are the zeros of a cubic function, then \(a=\sqrt{6}\), \(b=\sqrt{6}\), \(c=3\)

\[(x-a) ( x-b) ( x - c ) = 0\]
\[(x-\sqrt{6}) ( x-\sqrt{6}) ( x - 3 ) = 0\]

Answer 3

Erm \(b=-\sqrt{6}\) sorry

Answer 4

It's \[\sqrt{6}, -\sqrt{6}, -3 \] not both positive

Answer 5

And the -3 as well

Answer 6

Yeah

Answer 7

Lol yeah :)

Answer 8

Just use this and expand it and you'll get your cubic function.

Answer 9

uhm okayy

Answer 10

Let's see \[(x−\sqrt{6})(x+\sqrt{6})(x+3)=0 \\ \\ \]

Answer 11

\[(x−\sqrt{6})(x+\sqrt{6})(x+3)=0 \\ \\ (x^2-6)(x+3)=0 \\ \\ x^3+3x^2-6x-18=0\]

Answer 12

Oh! I get it now! Thanks!!

Answer 13

Yw :)