Solve:
a) {-4, 2} b) {-2, 4} c) {}
The first step is to cross multiply : \[\Large \frac{x+4}{4} =\frac{x}{x-2} \] \[\Large 4(x) = (x+4)(x-2)\]
what do you do next?
Simplify on both sides. So you multiply 4 by x to get 4x and (x+4) by (x-2) Do you know how to do that last part ?
not right off
Het thomas ;)
I'm sorry I'm back. Basicaly you do what is called FOILing in order to find the appropriate expression. You can practice here: http://www.mesacc.edu/~scotz47781/mat120/notes/polynomials/foil_method/foil_method_practice.html Foil stands for: First Outer Inner Last Basically a systematic way to multiply each other together: \[\Large (x+4)(x-2) = (x*x) + (x)(-2) + (4)(x) + (4)(-2)\]
and at no point in time were you wrong
Basically you get 4x on the left hand side and the RHS is \[\Large (x+4)(x-2) = x^2-2x-8\]
1
so is the awnser -4 and 2
\[\Large 4x = x^2-2x-8\] Solving for x gets you \[\Large 4x - \color{blue}{4x} = x^2-2x-8 - \color{blue}{4x}\] \[\Large 0 = x^2-6x-8\] (x+2)(x-4) x= -2 x = 4
thank you
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