Question

the solutions to y^2 - 2y +3 = 0

Do I factor it out? (y+1) (y- 3) ? I will give you a shiny medal if you help :) I dont want to plug in numbers either and I kind of forgot my math knowledge which makes me sad. So please give me detailed instructions! Thank you :)

Answer 1

i think your statement should be \[y^2-2y-3=0\]

Answer 2

Oh, but the question is y^2 - 2y +3 = 0

Answer 3

then it has complex solutions as i have made factors.

Answer 4

oh okay, so do I use some kind of quadratic formula?

Answer 5

yes, you will get complex solutions.

Answer 6

?

Answer 7

@jhonyy9 Are you busy? Can you help me with this? is it:

Answer 8

a=1,b=-2,c=3

Answer 9

your formula is correct.

Answer 10

oh but isnt the coefficient for y^2 - 2y +3. y =a ?

Answer 11

i already have solved above by making factors.

Answer 12

ahh I see

Answer 13

so I get \[\sqrt (-2^2) - 4 (1) (3) / 2(1) +-3/2 ?\]

Answer 14

\[y=\frac{ -(-2) \pm \sqrt{(-2)^2-4 \times 1 \times 3} }{ 2 \times 1 }\]

Answer 15

I got -3/2 + 8/2 for the addition one. And the subtraction one: -3/2 - 8/2

Answer 16

no,\[y=\frac{ 2 \pm \sqrt{4-12} }{ 2 }=\frac{ 2 \pm \sqrt{-8} }{ 2 }=\frac{ 2 \pm \sqrt{4 \times2 \times -1} } { 2 }\]
\[y=\frac{ 2 \pm2\sqrt{2 \iota ^2} }{ 2 }=1 \pm \sqrt{2} \iota \]

Answer 17

i deleted because i have written y2+2 y+3=0

Answer 18

where did the i^2 come from?

Answer 19

\[\iota ^2=-1\]

Answer 20

hmm so I dont need to subtract or add anything? Just leave it as +/- ?

Answer 21

this is iota not i

Answer 22

you can write
\[y=1+\sqrt{2}\iota ~and~y=1-\sqrt{2}\iota\]

Answer 23

1±2√2i How does it become a 1? Because I got -2 1± √2i

Answer 24

\[\sqrt{-8}=\sqrt{2\times 2 \times2\times-1}\]

Answer 25

\[\frac{ p+q }{ 2 }=\frac{ p }{ 2 }+\frac{ q }{ 2 }\]

Answer 26

wait no I got \[-2 \pm \sqrt 2(2)(2)i\]

Answer 27

-2/2 = -1 ± \[\sqrt 2i\]

Answer 28

\[y=\frac{ 2 }{ 2 }\pm \frac{ 2\sqrt{2}\iota }{ 2 }=1\pm \sqrt{2}\iota\]

Answer 29

but the quadratic formula is -b? :0

Answer 30

-(-2)=2

Answer 31

b=-2

Answer 32

-b=-(-2)=2

Answer 33

Ooooh!!!! omigosh, so the -b meant that we have to multiply a -1 to the b?

Answer 34

correct

Answer 35

oh my gosh I see now I got the same answer as you! 1−/+ √2ι

Answer 36

Thank you so much for helping me! I understand now! :DD

Answer 37

yw

Answer 38

thanks again and everyone :D