Question

A piece of wire 25mm long and with a rectangular cross section, having a high of 5µm and width of 1mm, has a resistance of 122mΩ. What is the material it is made of?

Material ρ (Ωm) at 20 °C

Silver 1.59×10−8
Copper 1.68×10−8
Gold 2.44×10−8
Aluminium 2.82×10−8
Tungsten 5.60×10−8
Zinc 5.90×10−8
Nickel 6.99×10−8
Iron 1.0×10−7
Platinum 1.06×10−7
Tin 1.09×10−7
Carbon steel 1.43×10−7
Titanium 4.20×10−7
Stainless steel 6.9×10−7
Nichrome 1.10×10−6

Answer 1

R =pL/A

formula

Answer 2

Can u calculate rho=?
From ur given data

Answer 3

Rho=specific resistance

Answer 4

i m bit confused about the unit conversation etc can you please calculate it?

Thank you

Answer 5

the formula is given clearly above

YOU can calculate it

just convert all the dimensions to METRES first

Answer 6

I will convert the FORMULA for you:

R =pL/A -> p = RA/L

Answer 7

122mΩ = 122 *10^-3Ω

Answer 8

1 micrometre=10^-6 m

Answer 9

U know
1 mm=10^-3 m

Answer 10

Can u calculate cross sectional area of ur given wire A=?

Answer 11

A=weidth*height=?

Answer 12

A=1*10^-3m*5*10^-6m=?

Answer 13

I think u hv value of resistance R, cross sectional area A, length of wire L
Find out rho=?