Question

Plzz help....!!
Find a quadratic polynomial each whose zeroes are-3 & 2 respectively.

Answer 1

If the zeroes are -3 and 2 then the quadratic is
(x+3)*(x-2)=0
x^2 +x -6=0

Answer 2

How u done?

Answer 3

With the format (x-a)(x-b)=0 where a and b are the zeros

Answer 4

\[(x-a)(x-b)=0 \\ \\ (x-(-3))(x-2)=0 \\ \\ (x+3)(x-2)=0 \\ \\ ...\]

Answer 5

OK. Then we have to just put values of zeores and just multiply it

Answer 6

Not quite.
You put the values of the zeroes with OPPOSITE SIGNS.
Zeroes are -3 and 2 so we enter
(x+3)*(x-2)=0

Answer 7

Ohh.... Now I understand .........can u tell me the quad. Equation whose zeroes are1&1

Answer 8

My answer is x^2 +2x +1. But the answer is not matching with the book 's answer

Answer 9

You might be doing the expansion incorrectly (x+3)(x−2), try again

Answer 10

Find a quad. Polynomial whose zeroes are 1& 1

Answer 11

well enter the zeroes with opposite signs so we have
(x-1)*(x-1)=0

Answer 12

Then (x-1)*(x-1)
X^2 -x -x +1
X^2 -2x +1

Answer 13

With the expanded equation \(x^2-x-x+1\) from \((x-1)(x-1)=0\)

Answer 14

But the answer is x^2 -x +1. In place of x^2 -2x +1

Answer 15

No the answer is x^2 -2x +1
that other answer is wrong
the roots of x^2 -x +1 are imaginary (complex)

Answer 16

Okk... Let's take another question. Zeroes are 4&1 .... Find quad . polynomial....

Answer 17

The answer of this is x^2 -4x +1

Answer 18

@wolf1728

Answer 19

If a zero of a polynomial is A, then (x-A) is a factor of the polynomial. Conversely, P(A) = 0 if A is a zero of the polynomial P. (Factor theorem)

So for a quadratic with zeros being A and B, the resulting factorised polynomial is
(x-A)(x-B)

This means you sub in your zeros A, B into the factorised form (x-A)(x-B) and expand.

Answer 20

If zeroes equal 4 and1 the quadratic is
(x-4)*(x-1)=0
x^2 -5x +4 = 0