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OpenStudy (acespeedfighter):
What is the value of 1/2 x3 + 3.4y when x = 4 and y = 2? (4 points)
12.8
14.8
25.8
38.8
9 years ago
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OpenStudy (sachintha):
\(x^3 = x^2\times x= x\times x\times x\)
Now try to write the expression by substituting the values.
9 years ago
OpenStudy (acespeedfighter):
hmmm
9 years ago
OpenStudy (acespeedfighter):
so its C
9 years ago
OpenStudy (sachintha):
Nope. Show me the expression after substituting the values.
9 years ago
OpenStudy (acespeedfighter):
Im not good at math sadly ;-;
9 years ago
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OpenStudy (sachintha):
\(\frac{1}{2}x^3+3.4y=\frac{1}{2}(4)^3+3.4(2)\)
9 years ago
OpenStudy (acespeedfighter):
idk ;-;
9 years ago
OpenStudy (acespeedfighter):
brb
9 years ago
OpenStudy (prizzyjade):
\[\frac{ 1 }{ 2 } x^{3}+ 3.4y \]
substitute then the given value of y and x
9 years ago
OpenStudy (sachintha):
\(\frac{1}{2}x^3+3.4y=\frac{1}{2}(4\times 4\times 4)+3.4\times2\)
9 years ago
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OpenStudy (prizzyjade):
\[\frac{ 1 }{ 2 }x ^{3} + 3.4y = \frac{ 1 }{ 2 }(4^{3})+3.4(2)\]
9 years ago
OpenStudy (prizzyjade):
since \[4^{3}=4\times4\times4=16\times4=64\]
then \[\frac{1}{2} (4^3) + 3.4(2) = \frac {1}{2} (64)+ 3.4(2)\]
we can see that
\[\frac {1}{2} (64) = \frac {64}{2}\]
which is equal to 32.
\[32 + 3.4(2)= 32+6.8\]
\[=38.8\]
9 years ago
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