Express the complex number in trigonometric form. -3i
@baru can you help with this one and just one more?
think of it as: 0+3i can you find its magnitude?
3?
yep, so that complex number in trignometric form looks this way: \[3(\cos \theta + i \sin \theta)\] so i'm just going to factor out 3 from 0 + 3i to get 3(0 + i) so now the problem reduces to finding \(\theta\) such that \(cos \theta=0\) and \(sin \theta = 1\) so what is the value of \(\theta\) ?
I'm not sure..
you just need to find \(\theta\) such that cos\(\theta\)=0
0?
is cos(0) = 0 ?
yes
http://www.mathwords.com/t/t_assets/t80.gif look it up in that link, what is the value of cos(0) ?
It's 1?
Idk I'm sorry I'm not good at this
one way to find the angle is to plot the point (x is the real part and y is the complex part) in other words, think of 0-3i as (0, -3) |dw:1467898164921:dw|
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