HELP I forgot how to solve this!
HI!
for the first one, find \(g(-1)\) once you get that plug it in for \(f\)
you know how to find \(g(-1)\)?
sadly no :(
\[g(x)=\frac{1}{x}\\ g(\heartsuit)=\frac{1}{\heartsuit}\\ g(-1)=?\]
-1?
yes
next find \(f(-1)\)
-1?
oh no
\[f(x)=x^2+9x\\ f(\spadesuit)=\spadesuit^2+9\spadesuit\\ f(\xi)=\xi^2+9\xi\\ f(-1)=?\]
@misty1212 sorry my computer crashed i got -8
yes; that is the answer
so in the first blank i put -1 and in the second i put -8?
NO
that was the answer to the first one only \[f(g(-1))=f(-1)=-8\]
oh ok can you help me with the equation for the second part?
g(f(1/2)) means find the value of f(1/2) and then find g of this value.
It's more productive if you understand what g(f(x)) means. If g(x) = 1/x then g(f(x)) means replace the x in g(x) = 1/x with f(x), giving us 1/f(x) So g(f(1/2)) = 1/f(1/2)
do i did that and got 19/4?
f(1/2) = (1/2)^2 +9(1/2) = 1/4 + 9/2 = 19/4 Then g(f(1/2)) = g(19/4)
@mww so the answer for the second part is 19/4?
f(1/2) = 19/4 But what is g(f(1/2)) = g(19/4) ? You need to refer to your g function to find g(19/4) ; it's a two step question
im so confused can you please work it out with me?
what is g(x)?
19/4
never mind its 1/x
ok so g(x) = 1/x means to find what g is we take the reciprocal of the input, x
which is 19/4?
f(x) tells us we must square the input and add 9 lots of the input (x^2 + 9x) So f(1/2) = 19/4 by subbing in when our input in 1/2. However g(f(x)) means we take the reciprocal of f(x) our input So g(f(1/2)) means we do 1/f(1/2) = 1/(19/4) = 4/19
oh so its 4/19?
do you get how we obtained that answer? This is called function composition or function of a function. The answer you get from one function you plug in as the input for the new function as shown below: |dw:1467901352489:dw|
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