Question

can someone please help me out? fan and medal

Answer 1

What is the solution to x2 + 8x + 19 = 0 when written in the form a + bi?

Answer 2

x^2 sorry

Answer 3

@.Sam. @ganeshie8

Answer 4

@agent0smith do you think you can help me please

Answer 5

Im just having a tough time solving this. I keep getting weird answers. I have answer choices if anyone needs inspiration.. Im working on a work sheet with practice problems.

Answer 6

You can use the Quadratic Formula
(-i x+sqrt(3)-4 i) (i x+sqrt(3)+4 i)

Answer 7

What do I plug in there?

Answer 8

Solve for x:
x^2+8 x+19 = 0
x = (-8±sqrt(8^2-4×19))/2 = (-8±sqrt(64-76))/2 = (-8±sqrt(-12))/2:
x = (-8+sqrt(-12))/2 or x = (-8-sqrt(-12))/2
sqrt(-12) = sqrt(-1) sqrt(12) = i sqrt(12):
x = (-8+i sqrt(12))/2 or x = (-8-i sqrt(12))/2
sqrt(12) = sqrt(4×3) = sqrt(2^2×3) = 2sqrt(3):
x = (i×2 sqrt(3)-8)/(2) or x = (-i×2 sqrt(3)-8)/(2)
Factor 2 from -8+2 i sqrt(3) giving 2 (i sqrt(3)-4):
x = 1/22 (i sqrt(3)-4) or x = (-2 i sqrt(3)-8)/(2)
(2 (i sqrt(3)-4))/(2) = i sqrt(3)-4:
x = i sqrt(3)-4 or x = (-2 i sqrt(3)-8)/(2)
Factor 2 from -8+-2 i sqrt(3) giving 2 (-i sqrt(3)-4):
x = i sqrt(3)-4 or x = 1/22 (-i sqrt(3)-4)
(2 (-i sqrt(3)-4))/(2) = -i sqrt(3)-4:
Answer: |
| x = i sqrt(3)-4 or x = -i sqrt(3)-4

Answer 9

Those are the choices..

Answer 10

So c then?

Answer 11

Yes.the third option.

Answer 12

whoa....
\[x= \frac{ - b \pm \sqrt{b^2-4ac} }{ 2a }\]
Where:
a=1
b=8
c=19
\[x= \frac{ -8 \pm \sqrt{8^2 -4(1)(19)} }{ 2(1) }\]
Plug this^^^^^^^^ into your calculator or an online one. Doesn't matter.

Answer 13

Thank you so much!! I have one more question. I just need help verifying something. Do you think if i open a new question someone could help me out? :)

Answer 14

Start a new question. @angiepangie0726