Question

what do you need to do to x=sec(t) to get 1/x=cos(t)?

Answer 1

you know how secant and cosine are related?

Answer 2

sec =1/cos

Answer 3

yes exactly so than you know that sec(t) = 1/cos(t) so than result that cos(t) = 1/sec(t)

given that x = sec(t) so from above wrote you know that 1/sec(t) = cos(t)

x= sec(t) =>x = 1/cos(t) so 1/x = cos(t)

hope this will help you

Answer 4

for example \[\sec(t)=2\iff \cos(t)=\frac{1}{2}\]

Answer 5

for instance.. how would you solve arcsec2 ?

Answer 6

you are solving \[\sec(x)=2\] so you would solve it just like the one i wrote above

Answer 7

i.e. you need to solve \[\cos(t)=\frac{1}{2}\]

Answer 8

pi/3?

Answer 9

yes

Answer 10

oh thank you! you can test me if you want

Answer 11

arctan(-1)=?

Answer 12

@zepdrix ..is it 3pi/4?

Answer 13

I don't know :(

Answer 14

You have the right idea...
but these inverse functions bring a long a new set of problems.

The range of our inverse tangent function is -pi/2 to pi/2.
so with arctan, your resulting angle should always lie in the 1st or 4th quadrant.

Answer 15

3pi/4 doesn't lie in either of those quadrants, ya? :|
There is another angle which gives us -1 when we take the tangent of it.