Question

I'm going to post a picture. Help needed badly.

Answer 1

Area of a square = s², where s is the side length.

For ABCD:
\[A=\left( 7x^{\frac{ 3 }{ 2 }} \right)^2\]

Answer 2

Can you simplify that?

Answer 3

@waterlover9150802

Answer 4

i have a question

Answer 5

@peachpi

Answer 6

since the outer square isn't a perfect square, wouldn't it mean that you can't multiply it by one other?

Answer 7

if you take a *square root*, a "not perfect square" is inconvenient.

but here you are squaring an expression, and you can always do that.

\[ \left( 7 x^\frac{3}{2}\right)^2 = 7 \cdot x^\frac{3}{2} \cdot 7 \cdot x^\frac{3}{2} \]

Answer 8

ok @phi thank you

Answer 9

i got 49 x^3 is that right?

Answer 10

you can change the order when multiplying so you can do
\[ 7\cdot 7 \cdot x^\frac{3}{2} \cdot x^\frac{3}{2} \\ = 49 x^3
\]

Answer 11

then for c would i have to do 49x^3-9x

Answer 12

yes
or
x(49 x^2 -9)

not a better way to write, just a different way.

Answer 13

ok