Question

I need help

Answer 1

What is the molarity of an aqueous phosphoric acid solution if 14.40 mL is completely neutralized by 20.28 mL of 0.1503 M NaOH?

Calculate the moles of H3PO4 at the dilution based on the volume and molarity of NaOH used.

Answer 2

@Jadeishere

Answer 3

I can't help right now, I'm so sorry!!!!!! I swear if I had more time to explain how to do this, I would, and yeah... So sorry :( Any other time, but I have to go to work... So extremely sorry

Answer 4

Don't worry about it. Take care :)

Answer 5

Calculate Mole NaOH.

Answer 6

How? Molar mass of NaOH x 1/3 ?

Answer 7

0.2028/0.1503

Answer 8

1.3493 ?

Answer 9

Good.

Answer 10

Now write the balanced equation of the chemical reaction.

Answer 11

H3PO4 + 3 NaOH → Na3PO4 + 3 H2O

Answer 12

Is that right?

Answer 13

@AaronAndyson

Answer 14

Looks good.

Answer 15

Now using the formulas you can solve the question.

Answer 16

so it is 1.343 mol NaOH x (1 mol H3PO4 / 3 mol NaOH) is 0.4498?

Answer 17

Right?

Answer 18

https://www.quora.com/What-is-the-molarity-of-a-phosphoric-acid-solution-if-358-mL-is-completely-titrated-by-a-876-mL-of-0-0102-M-barium-hydroxide-solution

Answer 19

I am so confused. x_X

Answer 20

All I need is to calculate the moles of H3PO4. :/

Answer 21

The number of moles of H3PO4 is just one-third the number of moles of NaOH.
So we can write the number of moles of H3PO4 (n) as:\[n = \frac{1}3 M_{NaOH}V_{NaOH}\]