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[PHYSICS PROB] Squids rely on jet propulsion to move around. A 1.5 kg squid drifting at 0.40 m/s suddenly expels 0.10 kg of water backward to quickly get itself moving forward at 2.5 m/s. If drag is ignored over the small interval of time needed to expel the water (the impulse approximation), with what speed relative to itself does the squid eject the water?
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Conservation of momentum?
Yes. Magnitude of change in momentum of water = change in momentum of squid
\[\Large m_{water} \Delta v_{water} = m_{squid} \Delta v_{squid}\]
oh so .10(v-.40)=1.5(2.5-.40) . . . v= 31.9 m/s
Actually since it says relative to itself, so i think you can ignore the initial 0.4m/s for the water
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.10(v)=1.5(2.5-.40)
thanks
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