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Mathematics 9 Online
OpenStudy (chupacabraj):

[PHYSICS PROB] Squids rely on jet propulsion to move around. A 1.5 kg squid drifting at 0.40 m/s suddenly expels 0.10 kg of water backward to quickly get itself moving forward at 2.5 m/s. If drag is ignored over the small interval of time needed to expel the water (the impulse approximation), with what speed relative to itself does the squid eject the water?

OpenStudy (chupacabraj):

Conservation of momentum?

OpenStudy (agent0smith):

Yes. Magnitude of change in momentum of water = change in momentum of squid

OpenStudy (agent0smith):

\[\Large m_{water} \Delta v_{water} = m_{squid} \Delta v_{squid}\]

OpenStudy (chupacabraj):

oh so .10(v-.40)=1.5(2.5-.40) . . . v= 31.9 m/s

OpenStudy (agent0smith):

Actually since it says relative to itself, so i think you can ignore the initial 0.4m/s for the water

OpenStudy (agent0smith):

.10(v)=1.5(2.5-.40)

OpenStudy (chupacabraj):

thanks

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