How do I cross multiply -2/4 by 2/sqrt(2)?
\[-\frac{ 2 }{ 4 }=\frac{ 2 }{ \sqrt{2} }\]like this?
-2/4 * 2/sqrt(2)
\[\frac{ 2 }{ 4 }\times \frac{ 2 }{ \sqrt{2} }\]
Yes
alrite
I'm sorry if I got the terms wrong. This isn't my strongest point in math, and I'm struggling with this concept - moreso since I'm currently working on the unit circle
So an explanation would really be helpful
it's okay.. step 1:simlifyit it until it is in simplest form\[-\frac{ 2 }{ 4 }\times \frac{ 2 }{ \sqrt{2} }\]
*simplify
How do I simplify the 2 and the square root of 2? or am i completely off .-.
\[-\frac{ 1\cancel{2} }{ 2\cancel{4} }\times \frac{ 2 }{ \sqrt{2} }\]
okay…
So 1/sqrt(2) ?
then,s\[-\frac{ 1 }{ 1\cancel{2} }\times \frac{ 1\cancel{2} }{ \sqrt{2} }\]
Okay, I see where that comes from! Cool!
it should hv the negative sign.. :)
*-1/sqrt(2) … sorry, figured haha
So the only option I see for the answer is -sqrt (2)
Is there another step to that?
yep
hint:\[a^-{\frac{ 1 }{ 2 }}=\frac{ 1 }{ a^{\frac{ 1 }{ 2 }} }\]
so would the -1 / sqrt(2) become -sqrt(2) according to that then?
or am i totally off
lt will be like this \[-\frac{ 1 }{ \sqrt{2} }\]\[=\frac{ 1 }{ 2^{\frac{ 1 }{ 2 }} }\]
yep,that's right!
WOOOOOO YEA
Thank you so much! :DDD I really appreciate it
yw! :)
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