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Mathematics 17 Online
OpenStudy (mathguy5):

Can someone explain how to do this please. http://prntscr.com/bqt0kl

zepdrix (zepdrix):

\(\large\rm f=3x\qquad\qquad\qquad g=x+2\) For a, we'll take our g function and stick it inside of our f function. What this means is, we're replacing the x in f, with the entire g function. \(\large\rm f\circ g=3g\) g is defined to be x+2, so we'll put that in place of our g, with parenthesis around it, so the multiplication works out correctly, \(\large\rm f\circ g=3(x+2)\)

zepdrix (zepdrix):

Too confusing? What do you think? :)

OpenStudy (mathguy5):

Ill try to review what you wrote down and tell you if I figured it out. Thank you :)

zepdrix (zepdrix):

If you're able to understand this concept, try applying the same idea to part b. \(\large\rm g=x+2\) In part b, we're sticking f into g. \(\large\rm g\circ f=f+2\)

OpenStudy (mathguy5):

@zepdrix Can you help me with this 1? http://prntscr.com/bqtn5g

zepdrix (zepdrix):

\[\large\rm f=\color{orangered}{x}^2+1\qquad\qquad\qquad g=\sqrt{8-x}\]Ok this one is a little trickier, same idea though. We'll take g and stuff it inside of our f function,\[\large\rm f\circ g=\color{orangered}{g}^2+1\]

zepdrix (zepdrix):

And then we replace g with what it actually is ya?\[\large\rm f\circ g=(\sqrt{8-x})^2+1\]

OpenStudy (mathguy5):

Yes I got -x+9 but my study guide says the answer is 9-x

zepdrix (zepdrix):

Those are equivalent. Maybe try to get a little stronger in arithmetic :) \(\large\rm 9-x\quad=9+-x\) You can rewrite subtraction as `addition of a negative`. From there, we know that addition is `commutative`, we can add in any order. So therefore, \(\large\rm 9+-x=-x+9\)

zepdrix (zepdrix):

Part b is a bit more difficult. When you have a composition of functions, you have to respect the domain of the `inner function` as well as the domain of the `resulting composite function`.

zepdrix (zepdrix):

The resulting function is pretty straight forward, -x+9 has no restrictions, all real numbers are ok. But we need also look at the function which we "stuck inside", and make sure it doesn't have any restrictions. \(\large\rm g=\sqrt{8-x}\) Do you understand how to determine the domain of this function g?

OpenStudy (mathguy5):

Yes I do. Thank you for all the help :)

zepdrix (zepdrix):

Ok good :) So just keep in mind that your resulting composite function will still carry the restrictions from g(x).

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