Question

Hydro static pressure

Answer 1

\(h_1=0.3\)m
\(h2=0.3\)m
\(h3=3.0\)m
\(\rho_1=700\)kg/m^3
\(\rho_2=800\)kg/m^3
\(dP=10000\)Pa
\(g=9.81\)m/s^2
Use hydrostatic equation at bottom of tank:
\(\rho_2*g*(h_3*sin(\theta) - h_2) = dP\)
Substitute all values and solve for \(\theta\).
I get 31.65 degrees.