PLEASE HELP! Which of the following exponential functions goes through the points (1, 12) and (2, 36)? f(x) = 4(3)−x f(x) = 3(4)−x f(x) = 3(4)x f(x) = 4(3)x
points (1, 12) and (2, 36) Plug in x=1, and then x=2, into each of the given functions.
KK
I just got (11,10) for the first two and than (12,24) for that last two
That doesn't make sense... First function: what is the value you get when you plug in x=1? And x=2?
4(3)-1 =11 4(3)-2 =10
Isn't the x an exponent...? What you did is not using exponents.
Right! you right! 12 for x=1 and 36 for x=2
Remember how to deal with negative exponents? Or you can just use a calculator, but you aren't following order of operations \[\large 4(3)^{-1}= 4\left( \frac{ 1 }{3 } \right)=\]
\[\large 4(3)^{-2 } = 4\left( \frac{ 1 }{ 3^2 } \right)=\]
1.3333 and 0.4444 is what my caulator gave me
Good, so does that look like a correct choice? Remember you're looking for the one that matches "points (1, 12) and (2, 36)"
well no that doesn't. wouldn't 3(4) be the same so A and B out out right?
B would not be the same. For B: what is the value you get when you plug in x=1? And x=2?
0.75 and 0.1875
Now do C and D.
12 and 48 for C 12 and 36 for D
therefore D is correct right?
Yes.
Thank you!
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