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Mathematics 19 Online
OpenStudy (wwb00):

Sigmatic Trig Function help

OpenStudy (wwb00):

\[\lim_{n \rightarrow \infty}(\sum_{\theta=0}^{n}(\sec(\theta*(\pi/4n))/(n+1))\]

OpenStudy (wwb00):

I am calculating the average of the lengths of every line coming from one vertex of a square. This came from my calculations, and I can not simplify the sigma within the limit.

OpenStudy (wwb00):

Does anyone have a plausible approach? I have graphed this and it converges but I want an exact solution.

OpenStudy (wwb00):

|dw:1468175089443:dw|

OpenStudy (wwb00):

I don't care about the other parts. Is there a way, any way at all, to do this Sigma?

OpenStudy (amistre64):

the line goes from one vertex all the way to another side?

OpenStudy (wwb00):

yes

OpenStudy (amistre64):

do you have to use the trig in it? or was that your own idea?

OpenStudy (wwb00):

my own idea. Is there a better way ?

OpenStudy (amistre64):

not sure if better is the right term ... but i was thinking of pythaging it. line^2 = side^2+height^2 as side does from 0 to side

OpenStudy (wwb00):

yes so are you supposing a related rate problem?

OpenStudy (amistre64):

something like that ...

OpenStudy (wwb00):

what is it that you suppose? could we define x and y parametrically?

OpenStudy (amistre64):

maybe, as x moves from 0 to 1 or whatever the side length is of the square d=sqrt(1+x^2) this gives us half the lines \[\int d=\int^{1}_{0}\sqrt{1+x^2}~dx\] as a start maybe?

OpenStudy (amistre64):

|dw:1468176393708:dw| times 2 gives us half the lines in the square right?

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