Sigmatic Trig Function help
\[\lim_{n \rightarrow \infty}(\sum_{\theta=0}^{n}(\sec(\theta*(\pi/4n))/(n+1))\]
I am calculating the average of the lengths of every line coming from one vertex of a square. This came from my calculations, and I can not simplify the sigma within the limit.
Does anyone have a plausible approach? I have graphed this and it converges but I want an exact solution.
|dw:1468175089443:dw|
I don't care about the other parts. Is there a way, any way at all, to do this Sigma?
the line goes from one vertex all the way to another side?
yes
do you have to use the trig in it? or was that your own idea?
my own idea. Is there a better way ?
not sure if better is the right term ... but i was thinking of pythaging it. line^2 = side^2+height^2 as side does from 0 to side
yes so are you supposing a related rate problem?
something like that ...
what is it that you suppose? could we define x and y parametrically?
maybe, as x moves from 0 to 1 or whatever the side length is of the square d=sqrt(1+x^2) this gives us half the lines \[\int d=\int^{1}_{0}\sqrt{1+x^2}~dx\] as a start maybe?
|dw:1468176393708:dw| times 2 gives us half the lines in the square right?
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